# The AnglÉ "On Taxes and Tea Parties"

Tea party at Salt Lake City's Capitol Hill: http://www.deseretnews.com/article/1,5143,705289328,00.html

(You might need to manually copy the whole URL as some video description fields don't recognize commas "," as valid parts of an internet address.)

National Debt as Percentage of GDP (60.8%-74.6%):

https://www.cia.gov/library/publications/the-world-factbook/geos/us.html

http://www.whitehouse.gov/omb/budget/fy2009/pdf/hist.pdf

No tax hikes during recession:

http://www.whitehouse.gov/omb/blog/09/02/26/Clearingupamisconceptiontaxhikesduringarecession/

Expiration of Bush Tax Cuts on upper brackets (income levels & percentages):

http://www.whitehouse.gov/the_press_office/Briefing-by-White-House-Press-Secretary-Robert-Gibbs-2/23/2009/

Sanpete Economic Numbers:

http://factfinder.census.gov/servlet/ACSSAFFFacts?_event=Search&geo_id=&_geoContext=&_street=&_county=Sanpete&_cityTown=Sanpete&_state=04000US49&_zip=&_lang=en&_sse=on&pctxt=fph&pgsl=010

Rush Limbaugh address to CPAC:

http://www.rushlimbaugh.com/home…

Duration : **8 min 57 sec**

the outer figure is a square.

(Here's why $latex angle ABC = 150^{circ}$. Suppose $latex angle ABD = x$. Then, from congruency of appropriate triangles, we have $latex angle ABC = 2x$. Now, note that $latex AC = AD = CD$ since the outer figure is a square. This allows us to compute $latex angle CAD$ in two ways. It is not hard to show that we have $latex angle CAD = 60^{circ} = 2x – 90^{circ}$, whence we have $latex angle ABC = 2x = 150^{circ}$.)

Of course, the way you stated the problem, it does not assume that the outer figure is a square, in which case, there is no unique solution as correctly pointed out by jd2718.]]>

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=> >> f.instance_variables

=> >> => "blue"

Wow, that first line was a mouthful, wasn't it?]]>

the outer figure is a square.

(Here's why $latex angle ABC = 150^{circ}$. Suppose $latex angle ABD = x$. Then, from congruency of appropriate triangles, we have $latex angle ABC = 2x$. Now, note that $latex AC = AD = CD$ since the outer figure is a square. This allows us to compute $latex angle CAD$ in two ways. It is not hard to show that we have $latex angle CAD = 60^{circ} = 2x – 90^{circ}$, whence we have $latex angle ABC = 2x = 150^{circ}$.)

Of course, the way you stated the problem, it does not assume that the outer figure is a square, in which case, there is no unique solution as correctly pointed out by jd2718.]]>